Which function(s) have this graph?
y = -sin(x)
y = -cos(x - π/2)
y = cos(x + π)
y = sin(x - π/2)
y = -cos(x)
y = sin(x + π)

Question

Which function(s) have this graph?
y = -sin(x)
y = -cos(x - π/2)
y = cos(x + π)
y = sin(x - π/2)
y = -cos(x)
y = sin(x + π)

anonymous · Answer

attachment

demandandsupply · Answer

That is a sine graph that has been shifted to the left

demandandsupply · Answer

EG, F(x+3) means that the graph is shifted to the left by 3 units, so apply the same principle

anonymous · Answer

y = sin(x - π/2) ?

demandandsupply · Answer

Where does the graph cross the x axis on the left side of the y axis?

anonymous · Answer

- π

demandandsupply · Answer

Good, so the actual sign graph starts from (0,0), so its shifted to the left by - pi

anonymous · Answer

so would it be sin(x-π)?

anonymous · Answer

there no option for that

demandandsupply · Answer

In the example i gave with the +3, when the sign is in the brackets, it shifts the opposite way to what you might think, so its sin(x+pi)

usukidoll · Answer

this is definitely a sinx graph so all the cosx options are thrown out immediately

usukidoll · Answer

if there's a - sign it means reflection and I don't see that so that choice is gone.. I agree with the last option

anonymous · Answer

apparently its not just the last one

anonymous · Answer

when i select the last, i got it wrong

could it be -sin(x)

demandandsupply · Answer

So it's more than one of them?

anonymous · Answer

yes, or either this one is wrong

demandandsupply · Answer

So i think it has to be one with a 'plus', because the graph has been shifted to the left

usukidoll · Answer

-sin(x) is a reflection of sinx how could that be?

usukidoll · Answer

|dw:1398941812354:dw| that is the original sinx graph ... the graph you were given is stretched out and shifted.