HELP!!!!!!

Solve.

x2 + 5x – 6 = 0

A.

{1, –6}

B.
{2, 3}

C.

{–1, 6}

D.

{–2, –3}

Question

HELP!!!!!!

Solve.

 

    x2 + 5x – 6 = 0
	
	
 
A.
	

{1, –6}
	
 
B.
	{2, 3}
	
 
C.
	

{–1, 6}
	
 
D.
	

{–2, –3}

anonymous · Answer

$$x ^{2}+5x-6 =0$$ is what you mean right?

anonymous · Answer

its C

anonymous · Answer

oh sorry. no its A

anonymous · Answer

Yeah A is correct :D

anonymous · Answer

for this, you have a variable with a squared to start off with! this means you are going to have two answers. if i said x^2 equals 9 you automatically think 3 is the answer. -3 can also be though! to solve an equation like this where it is equal to zero, you wanna set it up in this form!
(x    )(x    )=0

anonymous · Answer

okay thank you and @jeremyggg can you keep explaining it?

anonymous · Answer

you wanna think of your last number of -6. what two numbers can you multiple by that will equal -6 but when added together will equal 5?

anonymous · Answer

+6 and -1 right?
 6*-1 = -6 
and 
6+-1 = 5 so those are your two numbers you add to the (x  )(x   ) =0
(x + 6)(x-1)=0

anonymous · Answer

from here, we know that any number *0=0 soooo there are two numbers that you can use to make either of those equal 0! if x was 1 the (x-1) would be 0! or.... if x was -6 
(x+6) would equal 0!

anonymous · Answer

thank you

anonymous · Answer

seems tough, but the steps for anything x^2 +x + c = 0
1)put it in this form (x   )(x   ) = 0
2)then make each parenthesis equal 0!