Will give medal and fan...

What are the explicit equation and domain for an arithmetic sequence with a first term of 6 and a second term of 2?

an = 6 − 2(n − 1); all integers where n ≥ 1

an = 6 − 2(n − 1); all integers where n ≥ 0

an = 6 − 4(n − 1); all integers where n ≥ 0

an = 6 − 4(n − 1); all integers where n ≥ 1

Question

Will give medal and fan...

What are the explicit equation and domain for an arithmetic sequence with a first term of 6 and a second term of 2? 

an = 6 − 2(n − 1); all integers where n ≥ 1

an = 6 − 2(n − 1); all integers where n ≥ 0

an = 6 − 4(n − 1); all integers where n ≥ 0

an = 6 − 4(n − 1); all integers where n ≥ 1

anonymous · Answer

@hartnn @studygeek15

hartnn · Answer

ok, so  $a_1 = 6, a_2 =2 $
can you find the common difference 'd' from here ?

hartnn · Answer

then you would just use the formula
$\Large a_n = a_1+(n-1)d$
where a1 = 1st term = 6 and d =...

anonymous · Answer

I will try it (:

hartnn · Answer

good, common difference is difference between consecutive terms, like 2nd term - 1st term = 3rd term -2nd term =...and so on

anonymous · Answer

Is it a?

hartnn · Answer

d = 2nd term - 1st term = 2-6 = ... ?

anonymous · Answer

-4... so it is D then?

hartnn · Answer

yes! it is, because n always starts from 1 :)

anonymous · Answer

Alright! That makes sense. Thank you so much!! :D

hartnn · Answer

welcome ^_^