how do I solve 3/2x+1/2=10/4x
how do I do that
\[\frac{3}{2x}+\frac{1}{2}=\frac{10}{4x}\]\[6+2x=10\]\[2x=4\]\[x=2\]
thank @twvogels is it okay if you help me with 2 more like this
@RadEn can you help me please
what you question ?
* your
solve
\[x/4-x/12=1/2\]
well, this is one of way to solve the equation above. x/4 - x/12 = 1/2 first, the LCM of (4,12,2) = 12 so, times by 12 on the left side and right side then simplify, get 12 (x/4 - x/12) = 12 * 1/2 3x - x = 6 2x = 6 then divided by 2 on both sides, get 2x/x = 6/2 x = 3
thanks I have one more can you help me with it please @RadEn
\[x+\frac{ 12 }{ x}=7\]
no problem. please, post it
I just did
ok, first multiply by x on both side then simplify get x + 12/x = 7 x(x + 12/x) = 7 * x x^2 + 12 = 7x subtract by 7x on both side, get x^2 - 7x + 12 = 0 factor out to make the zeroes : (x - 3)(x - 4) = 0 then set up all factor be zero, then solve for x : x-3 =0 get x = 3 x-4 =0 x = 4 so, as the solution = {3,4}
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