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Mathematics 19 Online
OpenStudy (anonymous):

Use L'hopital rule , fan and medal

OpenStudy (anonymous):

\[\lim_{x \rightarrow 0}\frac{ \left( lnx \right) ^{2}}{(x-1)^{2}}\]

OpenStudy (solomonzelman):

have you tried to derive top and bottom?

OpenStudy (anonymous):

i can't bcoz it should equal 0/0 or inf/inf to derive the top and bottom

OpenStudy (anonymous):

that what l'hopital rule says

OpenStudy (solomonzelman):

oh yeah... then idk, I am not good at this stuff -:(

OpenStudy (solomonzelman):

john weldon probably knows....

OpenStudy (anonymous):

@SolomonZelman thanks , @johnweldon1993 can u help me ?

OpenStudy (anonymous):

@Abdulhameed halla habibi :)

OpenStudy (anonymous):

You take the derivative of the top and the derivative of the bottom and then you plug in the limit that is given. If the limit still gives a l'hopitals case, you do it again.

OpenStudy (anonymous):

@Boblovesmath halla bek :D

OpenStudy (anonymous):

@Boblovesmath i know but it should equal 0/0 or inf/inf to do that and in this question it doesn't

OpenStudy (johnweldon1993):

Sorry just got back on this question lol... L'Hopital cannot be applied here since "as you pointed out" it is not in indeterminant form It would indeed have to be 0/0 or infinity times infinity

OpenStudy (anonymous):

so if you plug in zero you should get the value of the limit..... You don't need to use l'hopitals, you only use when in intermediate forms.

OpenStudy (anonymous):

@johnweldon1993 i know it cannot be applied so i have to do something to make it can be applied

OpenStudy (johnweldon1993):

That is because that IS the limit...this function approaches infinity as x approaches 0

OpenStudy (anonymous):

then the limit of this function is infinity.....

OpenStudy (anonymous):

ok thank u all for helping , and can u help me with another one

OpenStudy (anonymous):

@Abdulhameed write the question and tag me in I will help you. :)

OpenStudy (anonymous):

it's about l'hopital too

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