What is the equation in point-slope form of the line passing through (-2, -5) and (2, 3)? fan and medal
@wolf1728
@TheRealMeeeee
any ideas on how to begin?
well i think its (y + 2) = -2(x + 5)
how did you get the -2?
becuase point slope formula is y-y=mx(x-x1) and the points (-2,-5) woul make the signs turn into postives
i meant the red two \[(y + 2) = \color{red}{-2}(x + 5)\]
to start, but point slope, you have almost correct for the formula, it's not mx, it's just m
this is my question
I just want you to tell me why
(-2,-5) and (2,3) first we need slope m=y2-y1/x2-x1 m=3+5/2+2 m=8/4 m=2. so far we have y=2x+b now sub in any point. i will use (2,3) where 2=x and 3=y 3=2(2)+b 3=4+b -1=b now we have our equaion. y=2x-1
those are my points
of course... you are guessing. I should have known. You shouldn't do that. It makes those helping you think you know something you do not. So, to start, what does the m represent?
oh sorry. i didn't do point slope form, idk what that is?
no im not guessing im trying to plug in the points uhh duuhh
this website should help. our teachers didn't teach us it, since they felt we had to go at a quicker pace but heres a website to help you http://www.purplemath.com/modules/strtlneq2.htm
okay its not -2 its either b or c
nvm its c i got the equation
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