Question

What is the equation in point-slope form of the line passing through (0, 6) and (1, 3)?

Answer 1

\(\bf \begin{array}{lllll}
&x_1&y_1&x_2&y_2\\
&({\color{red}{ 0}}\quad ,&{\color{blue}{ 6}})\quad &({\color{red}{ 1}}\quad ,&{\color{blue}{ 3}})
\end{array}
\\\quad \\

slope = {\color{green}{ m}}= \cfrac{rise}{run} \implies \cfrac{{\color{blue}{ y_2}}-{\color{blue}{ y_1}}}{{\color{red}{ x_2}}-{\color{red}{ x_1}}}
\\ \quad \\

y-{\color{blue}{ y_1}}={\color{green}{ m}}(x-{\color{red}{ x_1}})\qquad \\
\qquad \uparrow\\
\textit{point-slope form}\)

Answer 2

just plug in your slope and the coordinates as given

Answer 3

ok thanks :)

Answer 4

but when I do that i get y= -3x+6 which what i should get after doing all that but the options for an answer is

a. (y-3)= -3(x-1)
b. (y+3) = 3(x+1)
c. (y+3) = -3(x+1)
d. (y-3) = 3(x+6)

Answer 5

@jdoe0001

Answer 6

@robtobey