Question

Please help! solve for the indicated variable. Give the exact answers.

Answer 1

plug in sin t = x
then you will have a quadratic in 'x'
know how to solve quadratics ?

Answer 2

so can i do 3x^2=2x+1?

Answer 3

sure!
can you get 2 values of x from there ?

Answer 4

yes so you can get 0 or 1/2 correct?

Answer 5

no....how did u get those ?

Answer 6

by setting both sides equal to zero?

Answer 7

3x^2-2x-1 =0
3x^2-3x +x-1 =0
3x(x-1)+1(x-1) =0
....
know this method? its called factorizing...

Answer 8

so x= -1/3 and 1

Answer 9

thanks

Answer 10

yesss

so sin t = 1 and sin t = -1/3

can you find t from here ?

Answer 11

t = arcsin 1 = ....
t = arcsin (-1/2) = ...

Answer 12

sorry i left so the sin of t is 90 degrees because it never equals -1/3

Answer 13

why would sin t never = -1/3
?
and 90 degrees = pi/2 radians is one of the correct answers

Answer 14

on the unit circle it doesn't have -1/3

Answer 15

you see only standard angles on a unit circle :)

use calculator or google to find
sin inverse of (-1/2)

Answer 16

of (-1/3) ***

Answer 17

- pi/6

Answer 18

its -0.34 radians or -19.47 degrees
http://www.wolframalpha.com/input/?i=arcsin+%28-1%2F3%29

Answer 19

but you cant use that because it is not in the domain?

Answer 20

domain of sine is from -1 to +1
-1/3 lies within it :)

Answer 21

my original problem (the attachment) says [0, 2pi)

Answer 22

oh, so instead of -0.34, it would be
-0.34 +2pi = -0.34 + 6.28 =...

Answer 23

5.94 radians

Answer 24

thanks

Answer 25

do you mind helping me once more i am a little confused because this one contains sin and cosine... i can open it in a new one so that i can give you a new medal if you help me if you would like?

Answer 26

sure ask :)