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Probability 14 Online
OpenStudy (anonymous):

@ranga hi do you know how to do probability stuff?

OpenStudy (anonymous):

Yes

OpenStudy (anonymous):

I don't understand this, like questions 6-10

OpenStudy (anonymous):

Number 6 is asking how many times will you roll a 6 out of 40?

OpenStudy (anonymous):

i think so

OpenStudy (anonymous):

i don't really know :(

OpenStudy (anonymous):

Hm. I quite forgot this. I use to be good on this lol.

OpenStudy (anonymous):

lol yeah it's confusing me

OpenStudy (anonymous):

Sorry, problem some one could help you. Just bump your question again.

OpenStudy (anonymous):

probably*

OpenStudy (anonymous):

okey

OpenStudy (ranga):

Experimental probability of rolling a 6 = No. of times 6 was rolled / Total no. of times the dice was rolled = ?

OpenStudy (ranga):

The table tells you how many times 6 was rolled. The problem also tells you the total number of times the dice was rolled. Just plug the two numbers into the above formula.

OpenStudy (anonymous):

6=40/4?

OpenStudy (ranga):

The other way around. You have switched top and bottom.

OpenStudy (ranga):

P(rolling a 6) = 4 / 40 = 1 / 10

OpenStudy (anonymous):

oh you're smart

OpenStudy (anonymous):

thanks :)

OpenStudy (ranga):

You are welcome. For #7, first find P(rolling a 3) (use similar method as #6). Then P(NOT rolling a 3) = 1 - P(rolling a 3)

OpenStudy (anonymous):

I don't understand

OpenStudy (ranga):

In #6 we found P(rolling a 6). Use the same method first to find P(rolling a 3). DO that first and then we will do the next step.

OpenStudy (ranga):

P(rolling a 3) = No. of times 3 was rolled / Total no. of times the dice was rolled = ?

OpenStudy (ranga):

No. of times 3 was rolled is given in the table. Total no. of times the dice was rolled is given in the problem. Plug the two numbers into the above formula.

OpenStudy (anonymous):

2/40=

OpenStudy (anonymous):

?

OpenStudy (ranga):

Yes and you can simplify 2/40.

OpenStudy (ranga):

Two will go into both numerator and the denominator. So to simplify the fraction divide both the numerator and the denominator by 2.

OpenStudy (anonymous):

1/20

OpenStudy (anonymous):

whoa

OpenStudy (ranga):

Yes. P(rolling a 3) = 1/20. Whenever you know the probability of an event happening then you can easily find the probability of the event NOT happening by subtracting the probability from 1. P(NOT rolling a 3) = 1 - P(rolling a 3) = 1 - 1/20 = ?

OpenStudy (anonymous):

1-1/20=.95?

OpenStudy (ranga):

the decimal answer is correct. But subtract the fraction 1/20 from 1 and keep it as a fraction.

OpenStudy (anonymous):

how does that look?

OpenStudy (ranga):

a - b/c = (ac - b) / c 1 - 1/20 = (1*20 - 1)/20 = ?

OpenStudy (ranga):

To add or subtract fractions you will have to make the denominators the same. After that you can add or subtract the numerators. 1 - 1/20. To make the denominators the same, we can write 1 as 20/20. So 20/20 - 1/20 = (20-1)/20 = 19/20

OpenStudy (anonymous):

that looks confusing no offense

OpenStudy (ranga):

See if the method in my previous reply is easier to understand.

OpenStudy (anonymous):

i get understand that way when you put 20/20-1/20=19/20

OpenStudy (anonymous):

i meant to say 'i understand'

OpenStudy (ranga):

okay, the answer to 7 is 19/20.

OpenStudy (anonymous):

thank you

OpenStudy (ranga):

#8. P(rolling an even number) What are the even numbers in a dice?

OpenStudy (anonymous):

2,4,6?

OpenStudy (ranga):

Yes. P(rolling an even number) = P(2 or 4 or 6) = P(2) + P(4) + P(6) ---- (1) In #6 I showed you how to find P(6) and so we can use that same number in equation (1). Find P(2) and P(4) using the same method and plug it into equation (1).

OpenStudy (anonymous):

hmm

OpenStudy (anonymous):

for some reason im confused by the look of it

OpenStudy (anonymous):

it's just plugging in right?

OpenStudy (ranga):

Probability of rolling an even number = Probability of rolling a 2 or a 4 or a 6 = Probability of rolling a 2 + Probability of rolling a 4 + Probability of rolling a 6. From #6 we already know P(6) = 1/10. You just need to find P(2) and P(4) P(2) = No. of times 2 was rolled / Total no. of times the dice was rolled = ? P(4) = No. of times 4 was rolled / Total no. of times the dice was rolled = ? (I will have to leave shortly. Let us finish #8)

OpenStudy (anonymous):

oh If you have to leave it's ok, i can ask another person

OpenStudy (anonymous):

thanks for the help

OpenStudy (ranga):

You are welcome. Go through what we did in #6 to find P(6). Use the same method to find P(2) and P(4). Then just add P(2) + P(4) + P(6) to get your answer for #8.

OpenStudy (anonymous):

thanks

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