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Mathematics 21 Online
satellite73 (satellite73):

what is wrong with this question? solve for \(n\) \[-pn-40<70\]

OpenStudy (anonymous):

i suppose it's that, by solving for n, you're not solving for the definition of n. you're solving for what's greater than n.

OpenStudy (anonymous):

i could be out of the ballpark here tho

OpenStudy (anonymous):

yeah for example i could say solve for \(n\): \(-3n-40<70\) and do it no problem

OpenStudy (anonymous):

well p could be 0 or nonreal or undefined

OpenStudy (anonymous):

that's what gives it a problem

OpenStudy (anonymous):

er well being complex doesnt matter too much, but 0 or undefined

OpenStudy (anonymous):

ok lets stipulate that we know \(p\) is real, and non zero

OpenStudy (acxbox22):

if p was 0 the inequality would still be true -(0)n-40<70 -40<70

OpenStudy (anonymous):

but you couldnt solve for n?

OpenStudy (anonymous):

in that case you would have \((-\infty, \infty)\) as your solution no problem there

OpenStudy (anonymous):

guess it is not clear, which is why i saw this question earlier tonight

OpenStudy (primeralph):

p dependence will cause varying regions of solutions.

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