Question

PLEASE HELP! Standard form to vertex form: y=-x^2-12x-35

Answer 1

try to make a square first

Answer 2

The vertex form of quadratic function has the form:
y = a(x - h)^2 + k

Where (h , k) is the vertex

Answer 3

I can walk you through the steps to convert it if you like.

Answer 4

Yes please! @Hero

Answer 5

First, I would factor out the negative:

y = -(x^2 + 12x + 35)

Then divide both sides by -1 to get
-y = x^2 + 12x + 35

Next I observe that
(b/2)^2 = (12/2)^2 = (6)^2 = 36

The 36 is needed in order to be able to write the quadratic in square form.

Notice that 35 = 36 - 1 so

-y = x^2 + 12x + 36 - 1

Now we can write x^2 + 12x + 36 as (x + 6)^2 since it is in square form:

-y = (x + 6)^2 - 1


Now divide the both sides by -1 again to place the equation in proper form:
y = -(x + 6)^2 + 1

Answer 6

Start by 'completing the square'

Step 1) take the coefficient if the 'x' term and divide it by 2
Step 2) square the value u got from step 1
Step 3) insert that value between the 'x' term and the constant in your equation and subtract the same value from the constant on the end.

Good so far?

Answer 7

Thank you so very much! @Hero