@amistre64 I need you help

Question

@amistre64  I need you help

anonymous · Answer

$$\huge f(x) =x ^{3} -12x + 2 $$

anonymous · Answer

@thomaster

anonymous · Answer

@texaschic101

amistre64 · Answer

its a function ...

anonymous · Answer

I found first derivative

anonymous · Answer

i need maxima and minima

amistre64 · Answer

what is the slope of a line at a man or min?

amistre64 · Answer

max or min that is

anonymous · Answer

$$\huge 3x ^{2} -12$$

amistre64 · Answer

thats the first derivative, looks good

anonymous · Answer

i found the first derivative after that what i have to do

amistre64 · Answer

what does the first derivative define for us?

anonymous · Answer

I just don't know what i means i know that we have to set it =0 after that but really what does it mean

amistre64 · Answer

if you go back to the definition of a derivative:$$f'(x)=\lim_{h\to 0}\frac{f(x+h)-f(x)}{(x+h)-(x)}$$
this is nothing more than a funny looking definition of a slope.

amistre64 · Answer

so what this really tells us is what the slope of the line is at a given point

anonymous · Answer

oh so we have to draw a tangent ok fine

amistre64 · Answer

since f'(x) = 3x^2-12,  we now have an equation that tells us the slope of the line at any given point along the function x^3 - 12x + 2

anonymous · Answer

why do we set it = 0

amistre64 · Answer

a min or max occurs at the highest of lowest points of a graph, the slope at those points is a horizontal line,  a slope of 0

amistre64 · Answer

|dw:1399041875780:dw|