simplify? I came up with 9x^9. please check image.
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OpenStudy (anonymous):
OpenStudy (anonymous):
@Jadeishere
OpenStudy (jadeishere):
you're right >.<
OpenStudy (anonymous):
yesh
OpenStudy (jadeishere):
lol
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OpenStudy (anonymous):
i came up with 2n^4
OpenStudy (jadeishere):
yep
OpenStudy (anonymous):
woot woot!
OpenStudy (jadeishere):
xD
OpenStudy (anonymous):
i got 8a^2+4a-1
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OpenStudy (jadeishere):
it's 8a^2 - 4a + 1
OpenStudy (anonymous):
i was close
OpenStudy (jadeishere):
yep :)
OpenStudy (anonymous):
i got 32x^2 sqrt 6x
OpenStudy (jadeishere):
it's 22x^2(sqrt)6x
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OpenStudy (anonymous):
k
OpenStudy (jadeishere):
:)
OpenStudy (anonymous):
\[\sqrt{7}(\sqrt{28} -x)=9\]
OpenStudy (anonymous):
solving for x^^^
OpenStudy (anonymous):
\[\frac{ 5\sqrt{7} }{ 7 }\]
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OpenStudy (anonymous):
what i came up with^
OpenStudy (jadeishere):
yep!!
OpenStudy (anonymous):
The hypotenuse of a right triangle is 20 centimeters, and the shorter leg is 12 centimeters. Find the length of the other leg.
OpenStudy (anonymous):
i got 16cm
OpenStudy (jadeishere):
yep
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OpenStudy (anonymous):
Which of the following equations is of a parabola with a vertex at (0, 6)?
y = (x - 6)2
y = (x + 6)2
y = x2 - 6
y = x2 + 6
OpenStudy (anonymous):
i got the last one
OpenStudy (jadeishere):
(Let me graph it real quick >.<
OpenStudy (anonymous):
kk
OpenStudy (anonymous):
Find the vertex of the parabola whose equation is y = x2 + 2x + 9.
(-1, 8)
(1, 12)
(0, 9) <--- my answer
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OpenStudy (jadeishere):
you're right about the last two
OpenStudy (anonymous):
k
OpenStudy (anonymous):
Determine the solution set of (x - 3)2 = 49.
{6, -8}
{4, 10} <--- my answer
{10, -4}
OpenStudy (jadeishere):
10 and -4
OpenStudy (anonymous):
k
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OpenStudy (anonymous):
Solve x 2 + 10x + 7 = 0 by completing the square.
Which equation is used in the process?
(x + 10)2 = 93 <--- my answer
(x + 5)2 = 32
(x + 5)2 = 18
OpenStudy (anonymous):
totally lost on this next one.... see image
OpenStudy (jadeishere):
nope, you're incorrect about the (x + 10)^2 = 93
OpenStudy (anonymous):
so its???
OpenStudy (jadeishere):
hold on
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OpenStudy (jadeishere):
it's the last one, I believe
OpenStudy (anonymous):
ok
OpenStudy (anonymous):
please view the last one with image attached
OpenStudy (jadeishere):
i am
OpenStudy (anonymous):
thnx
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OpenStudy (jadeishere):
Um.. what i got doesn't make sense to me >.<
\[\frac{ 1 }{ 6(k^3 -156k^2 +190k-300) }\]
OpenStudy (anonymous):
ikr
OpenStudy (jadeishere):
Hm..
OpenStudy (jadeishere):
@OrangeMaster @Luigi0210
OpenStudy (anonymous):
What is the equation of the line, in general form, that passes through the point (-1, -1) and is parallel to the line whose equation is x + y = 3?
x - y + 2 = 0
x + y + 2 = 0 <--- my answer
x + y - 2 = 0
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OpenStudy (jadeishere):
yeah
OpenStudy (anonymous):
Perform the indicated operation.
(16m 2 + 40m + 25) ÷ (4m + 5) = _____
4m + 5 <-- my answer
4m + 15 R. -50
4m + 5 R. 50
4m + 15 R. 100
OpenStudy (anonymous):
@Novalynne help out please
OpenStudy (anonymous):
What is the center of the circle that has a diameter whose endpoints are (9, 7) and (-3, -5)?
(6, 6)
(3, 1)<--- my answer
(3, 4)
OpenStudy (anonymous):
these are the last two questions @Jadeishere
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OpenStudy (anonymous):
@NERD85176 please help out. the last two I just posted are my last two of the night
OpenStudy (anonymous):
@PinkSapphire want to help me out? Calling all genius's
OpenStudy (pinksapphire):
I wish I could help but I haven't learned this yet...Sorry :(