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Mathematics 17 Online
OpenStudy (anonymous):

Find the exact real value of arcsin(-square root of 3/2).

OpenStudy (anonymous):

pi/3 pi 7pi/3 -pi/3

OpenStudy (anonymous):

@zepdrix

OpenStudy (anonymous):

@douglaswinslowcooper

OpenStudy (anonymous):

This is the angle that has a sine of -sqrt(3)/2 look at triangle with sides 1 and sqrt(3) and hypotenuse 2, see what that angle is, then figure out how much more you need to increase it to get the sine to have a negative value, which puts the angle between pi and 2pi usually.

OpenStudy (anonymous):

pi/3? @douglaswinslowcooper

OpenStudy (anonymous):

or would it be negative?

OpenStudy (anonymous):

yeah it would be negative because there is a negative in front

OpenStudy (anonymous):

pi/3 would have a positive sine, move to pi/3 + pi = 4pi/3, but that is not an option, so go back from 0 to -pi/3 because sine is negative between 0 and - pi.

OpenStudy (anonymous):

so was i right?

OpenStudy (anonymous):

sin(-60 degrees) = -sqrt(3)/2 right

OpenStudy (anonymous):

so it would be pi/3 or -pi/3? you confused me

OpenStudy (anonymous):

sorry, your -pi/3 is correct

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