Find the exact real value of arcsin(-square root of 3/2).
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OpenStudy (anonymous):
pi/3
pi
7pi/3
-pi/3
OpenStudy (anonymous):
@zepdrix
OpenStudy (anonymous):
@douglaswinslowcooper
OpenStudy (anonymous):
This is the angle that has a sine of -sqrt(3)/2
look at triangle with sides 1 and sqrt(3) and hypotenuse 2,
see what that angle is, then figure out how much more you need to increase it to get the sine to have a negative value, which puts the angle between pi and 2pi usually.
OpenStudy (anonymous):
pi/3? @douglaswinslowcooper
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OpenStudy (anonymous):
or would it be negative?
OpenStudy (anonymous):
yeah it would be negative because there is a negative in front
OpenStudy (anonymous):
pi/3 would have a positive sine, move to pi/3 + pi = 4pi/3, but that is not an option,
so go back from 0 to -pi/3 because sine is negative between 0 and - pi.
OpenStudy (anonymous):
so was i right?
OpenStudy (anonymous):
sin(-60 degrees) = -sqrt(3)/2 right
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