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A farmer is designing a power line to carry current from 240V diesel generator to a farm house. He calculates that the maximum current required will be 40A and that the minimum satisfactory voltage at the house is 230V. What is the maximum value for the total resistance of the power line in order to achieve this?
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R=V/I, where R is resistance; V is voltage; and I is current.
Think about this, He has a 240 volt source and the load must receive no less than 230 volts. What does this mean?.........It means that he can not drop more than 10 volts over the transmission line when transmitting the maximum current of 40 Amps. Now doe you know what to plug into the formula provided by PsiSquared ? which is one version of Ohm's Law.
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