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For what number(s) x, with -2π< x < 2π, does sec(x +π/7) = 1?
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\(\sec(x +\dfrac{π}{7}) = 1\) Take inverse secant of both sides: \(x + \dfrac{\pi}{7} = \sec^{-1}(1)\) \(x = \sec^{-1}(1) - \dfrac{\pi}{7}\)
There's apparently more than one solution.
yea theres ment to be more than one solution
could you please help, i dont knw how to work it out??
Finding the rest of them has to do with the period of the secant function
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Do you know the period of secant function?
i recommend memorizing the periods of the main functions also i think you can solve for them using the unit circle but i could be wrong
There's one other solution that is most obvious if you know the period of the function
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