Question

if dy/dx = cos^2 (piy/4) and if y = 1 when x = 0, then when y = 3, x is equal to

Answer 1

if \[\frac{ dy }{ dx } = \cos ^{2}(\frac{ \pi y }{ 4 })\]and if y = 1 when x = 0, then when y = 3, x is equal to

1/8
-pi/8
1
8/-pi
8/pi

Answer 2

use double angle identity : \(\cos (2 x) = 2\cos^2x - 1 \)

Answer 3

and solve the diff eq'n first

Answer 4

\[\frac{ dy }{ dx } = \cos ^{2}(\frac{ \pi y }{ 4 })\]


\[\frac{ dy }{ dx } = \dfrac{1 + \cos( 2 \frac{\pi y}{4})}{2}\]

Answer 5

integrate