What was the hiker's average velocity during part A of the hike? http://static.k12.com/calms_media/media/1357500_1358000/1357620/1/185dd4e634bcb63a38595f220e8901f867258840/MS_PHYS_SCI_286559.jpg A. 0.17 km/h north B. 13.3 km/h west C. 5.0 km/h north D. 10 km/h north
Start with the fact that: $$velocity_{avg} = v_{final} - v_{initial}$$
okay that doesn't help much I'm not good with equations
No problem, this problem can be explained with a picture too.
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So let's break this problem down into parts. At first, the hiker heads north. He travels 5km over 30 minutes. What is his velocity for this part?
5km I think
Velocity is your change in distance over change in time
oh the the 30 minutes
So $$velocity = \frac{change\ in\ distance}{change\ in\ time}$$
so \[v=\frac{ 30 }{ 5 }\]
Almost! You have $$v = \frac{30\ minutes}{5\ km}$$ you need $$v = \frac{5\ km}{30\ minutes}$$
Remember, velocity is you change in distance, divided by your change in time.
so I got 166666666666667
with . in front
Right, so he travels 0.167 km for every minute that he walks.
but there is not a option for that how do I put it in hours
Easy! If you travel 0.167 km in one minute, how many km do you travel in one hour?
wouldn't I do 0.167*6 or 60
Yes! 60. You are correct.
I got 10.02
For every minute of walking, you travel 0.167 km. If you walked for 60 minutes, you would have $$ 0.167\ km \cdot 60\ minutes = 10.02 km$$
BUT! That's not the average velocity. Let's continue.
You need to find his velocity for all 4 parts, north, west, south, and east.
no for only part A like the question says
Oh! I'm sorry. I misread the question. I thought it said find the average velocity for the whole trip.
So yes, for every 1 hour of walking, the hiker will travel 10.07 km. So his velocity is 10.07 km/hr
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