If log65=1.812, what is the value of log 1000^65
?

A. 0.00182

B. 0.604

C. 0.0604

D. 0.1812

Question

If log65=1.812, what is the value of log 1000^65 
?

A. 0.00182

B. 0.604

C. 0.0604

D. 0.1812

anonymous · Answer

@tkhunny  ?

tkhunny · Answer

$\log(1000) = 3$

65*3 = 195

This causes me to wonder if I have the right problem statement.

anonymous · Answer

that isn't one of the options?

anonymous · Answer

@tgawade any idea on what the answer could be?

anonymous · Answer

|dw:1399149223614:dw|

anonymous · Answer

using    if  loga^b  =  b * loga

anonymous · Answer

So we will get    log65  /3* log10  so just  plug values &  simplify   we know that  
values of   log65 is  1.812  &  log10  is  1

anonymous · Answer

What do you get  ?

tkhunny · Answer

Is that it??

We have: $\log_{10}(65) = 1.812$

We want: $\log_{1000}(65) =\;??$

tkhunny · Answer

MUST work on the notation.  positions mean things.  Some things are arguments (65).  Some things are notations (1000).  Writing in line in this forum just is not the same as printing in a book.  You have to think about what you write and make sure you mean what you write.