Question

Write a quadratic variation equation if g(x) varies directly with x^2, and g(x) = 108 when x = 6.

Answer 1

well let k be the constant of variation

so the equation is

\[g(x) = k \times x^2\]

substitute x = 6 amg g(x) = 108

then solve for k

hope it helps

Answer 2

So g(6)=k*6^2 ?

Answer 3

not quite

108 = k * 6^2

Answer 4

108=k*36
\[108/36 =k\]

Answer 5

thats it

Answer 6

So g(x)=3x^2?

Answer 7

thats correct