Question

Suppose that x = ln(A) and y = ln(B). Write the following expressions in terms of x and y

ln(A-B)

Answer 1

log(A/B) = log(A) - log(B).
but.. log(A-B)... is there really a formula for this?

Answer 2

some new law i never saw before!

Answer 3

in the statement, did you mean ln(x-y) ?

Answer 4

@xlovely_Lizardx

Answer 5

I already tried that it's not right Campbell_st

Answer 6

you can't do it, that is why

Answer 7

yeah, I'm completely stumped

Answer 8

that's not an option though :0

Answer 9

I didn't think I could either but my professor didn't give me the option to put no solution or what ever

Answer 10

\(\ln(e^x-e^y)\)
that's all there is to say about this expression..

Answer 11

(if \(x>y\))

Answer 12

hold on

Answer 13

that's all I got

Answer 14

and "no" "no solution" "none" or "undefined" is not aloud as a possible answer

Answer 15

ok then ln(e^x - e^y) is the answer, because there's no formula for ln(a-b)

Answer 16

how did you find that?

Answer 17

from x = ln(A), y = ln(B).
you already found that A=e^x and B=e^y (see the answer to the question "e)" )

Answer 18

oh, that makes sense