more limits and derivatives XD
The position of an object at time t is given by s(t) = -8 - 9t. Find the instantaneous velocity at t = 1 by finding the derivative.
you know how to calc the derivative of the above formula?
just what it says take the derivative, plug in 1
since \(s(t)=-8-9t\) is a line, the derivative is the slope of the line, it is a constant, so it really has nothing to do with time 1 or any other time
wrong post!
oh my satellite.... thats why you dont bite off more than you can chew ;)
okay so -8-9(1)=-17
not really lovely
s'(t) = -9 regardless of what t is ;)
@satellite73 said the same above
I just don't see how a velocity can be -9 ??? It can get down to zero but negative???
velocity is just speed except it could be negative i..e you are going in reverse in this case you are going to the left
@satellite73 ah ok, sort of like a vector, thanks buddy
so did @lovelyharmonics get the answer or still wondering ?
im good c: lol thank you
Join our real-time social learning platform and learn together with your friends!