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Mathematics 14 Online
OpenStudy (lovelyharmonics):

more limits and derivatives XD

OpenStudy (lovelyharmonics):

The position of an object at time t is given by s(t) = -8 - 9t. Find the instantaneous velocity at t = 1 by finding the derivative.

OpenStudy (anonymous):

you know how to calc the derivative of the above formula?

OpenStudy (anonymous):

just what it says take the derivative, plug in 1

OpenStudy (anonymous):

since \(s(t)=-8-9t\) is a line, the derivative is the slope of the line, it is a constant, so it really has nothing to do with time 1 or any other time

OpenStudy (anonymous):

wrong post!

OpenStudy (lovelyharmonics):

oh my satellite.... thats why you dont bite off more than you can chew ;)

OpenStudy (lovelyharmonics):

okay so -8-9(1)=-17

OpenStudy (anonymous):

not really lovely

OpenStudy (anonymous):

s'(t) = -9 regardless of what t is ;)

OpenStudy (anonymous):

@satellite73 said the same above

OpenStudy (anonymous):

I just don't see how a velocity can be -9 ??? It can get down to zero but negative???

OpenStudy (anonymous):

velocity is just speed except it could be negative i..e you are going in reverse in this case you are going to the left

OpenStudy (anonymous):

@satellite73 ah ok, sort of like a vector, thanks buddy

OpenStudy (anonymous):

so did @lovelyharmonics get the answer or still wondering ?

OpenStudy (lovelyharmonics):

im good c: lol thank you

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