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Mathematics 13 Online
OpenStudy (lovelyharmonics):

graphing limits

OpenStudy (lovelyharmonics):

Use the given graph to determine the limit, if it exists. Find = limit as x approaches two from the right of f of x..

OpenStudy (anonymous):

when you approach 2 from the right then wouldn't it be f(x) = 4 ?

OpenStudy (reemii):

|dw:1399170148941:dw|

OpenStudy (lovelyharmonics):

i believe it is 4 but idk .-.

OpenStudy (reemii):

you are right.|dw:1399170466564:dw|

OpenStudy (lovelyharmonics):

so this one would be 4;-1 right?

OpenStudy (reemii):

4;-1 ?

OpenStudy (lovelyharmonics):

Use the given graph to determine the limit, if it exists. Find limit as x approaches two from the left of f of x. and limit as x approaches two from the right of f of x.. so its 4;-1

OpenStudy (reemii):

in which point are we taking the limit?

OpenStudy (lovelyharmonics):

lol idk

OpenStudy (reemii):

from the left, 4 from the right -1 ok, 4;-1 I understand the notation lol

OpenStudy (lovelyharmonics):

lol okay so this one Use the given graph to determine the limit, if it exists. Find limit as x approaches three from the left of f of x.. would be 7 and 1?

OpenStudy (reemii):

here you only ask for the limit from the left of 3. so just "1". not 7.

OpenStudy (lovelyharmonics):

so the 3;1

OpenStudy (reemii):

1;3 (1 on the left, 3 on the right)

OpenStudy (lovelyharmonics):

lol okay thank you for all the help c:

OpenStudy (reemii):

yw

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