Question

Help!!! will give medal.

Divide VVVV

Answer 1

Choices

Answer 2

Factor, factor, factor!!

Answer 3

OK, idk tht

Answer 4

help @paki

Answer 5

if u could show me in steps that can help but if u don't want to it ok

Answer 6

@paki

Answer 7

Reciprocal and multiply. That's all there is to it. Please demonstrate.

Answer 8

I don't know how @tkhunny

Answer 9

(x^2+2x+1)(x^2-4) / (x-2)(x^2-1) can you solve it now...

Answer 10

I do not believe that. Solve this: \(\dfrac{\dfrac{1}{9}}{\dfrac{1}{3}}\). Go!

Answer 11

hmmm ok hold on @paki gotta put it on paper

Answer 12

is it 1/3 @tk

Answer 13

How did you do that? Wasn't it "Reciprocal and Multiply"? That is ALL you need to do with these problems. Do EXACTLY the same thing.

Answer 14

I don't know what that is what are u talking about @tkhunny

Answer 15

hmm ok can u show me what goes next cuz im not shure @paki

Answer 16

@Anonymous16 little wait tkhunny is solving it....

Answer 17

ok

Answer 18

Still don't believe it.

\(\dfrac{\dfrac{(x^2+2x+1)}{(x^2-4)}}{\dfrac{(x-2)}{(x^2-1)}} \)

Reciprocal and Multiply

\(\dfrac{(x^2+2x+1)}{(x^2-4)}\cdot\dfrac{(x^2-1)}{(x-2)} \)

How was that different from (1/9)/(1/3)? It wasn't.

Answer 19

ok so now what I times

Answer 20

Factor.

\(\dfrac{(x+1)^{2}}{(x+2)(x-2)}\cdot\dfrac{(x+1)(x-1)}{x-2}\)

Not sure where this problem started. Looks like we went astray, somewhere. I would expect this to be the other way around.

\(\dfrac{(x+1)^{2}}{(x+2)(x-2)}\cdot\dfrac{x-2}{(x+1)(x-1)}\)

The, we could rearrange a little:

\(\dfrac{x+1}{x+1}\cdot\dfrac{x-2}{x-2}\cdot\dfrac{x+1}{(x+2)(x-1)}\).

Since I joined this party in the middle, I may not have started with the right problem. Anyway, that's the idea.

Answer 21

hmmm ok that is one of the answers that will work,, thank you for showing me @tkhunny

Answer 22

You do still have to modify additionally. \(\dfrac{x+1}{x+1} = 1\), away from x = -1.