Put the following radical expression into simplified form. Assume the variable represents a positive number.
\[\sqrt{\frac{ 48x^2y^3 }{ 7 }}\] Just can't seem to do these on my own correctly, ugh !
i know you can do it on your own :) try it!
I do, then it ends up wrong :/
go step by step numerator : factor 48
I got \[\frac{ 2xy^2\sqrt{21y} }{ 7 }\] That's incorrect...
y^2 out ? shouldn't that be just y
\(\sqrt {y^3} = \sqrt {y^2}\times \sqrt y \)
16*3, 16=4 \[4\sqrt{3}\]
4 sqrt 3 is correct so why did you put 2 instead of 4 ? :P
she mustn't been day dreaming - lol xD
there are only 2 mistakes in your answer
lol ugh, I can;t think straight right now lol
i was doing fine earlier,smh
first correction! make that 4 instead of 2 !
ah yes - uhm cookiibaii is it day at ur place?
ehh, kind of lol it is morning, but it 3 am
2nd correction \(\sqrt {y^3} = \sqrt {y^2}\times \sqrt y = y \sqrt y \)
there u go hartnn!
3am is the early start of the day, but overall to me 24 hours = 1 whole day. :P
Got it! Thanks!
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