A particle executes SHM with frequency 2.5 Hz and amplitude 2 m. The speed of the particle 0.3 s after crossing, the equilibrium position is????

Question

anonymous · Answer

please guys.... Help....

anonymous · Answer

y = (2) sin (5 pi t)   because f = 2.5/s  = 2.5 Hz  freqeuency

y' = dy/dt = (2)(5 pi) cos (5 pi t)    velocity from derivative

"equilibrium position" means? probably y =0 , so t=0 would work
thus 0.3s = t is where to evaluate y' from above.

anonymous · Answer

Yesss....... Thanks..... I totally forgot about that....