Question

Write the slope-intercept form of the equation for the line passing through the pint (-6, -5) and parallel to the line y=4x+6

Answer 1

hmm what's the slope of " y=4x+6 " ?

Answer 2

4/1

Answer 3

right.. 4/1 or just 4, and any parallel line to that one, will also have the same slope as thata one

so you'd want the equation of a line whose slope is 4 and passes through (-6, -5), or \(\bf \begin{array}{lllll}
&x_1&y_1\\
&({\color{red}{ -6}}\quad ,&{\color{blue}{ -5}})\quad
\end{array}
\\\quad \\

slope = {\color{green}{ m}}= 4
\\ \quad \\

y-{\color{blue}{ y_1}}={\color{green}{ m}}(x-{\color{red}{ x_1}})\qquad \textit{plug in the values and solve for "y"}\\
\qquad \uparrow\\
\textit{point-slope form} \)

Answer 4

So y-(-5)=4(x-(-6))?

Answer 5

yes, that'd give you the equation in point-slope form
but you're asked to give the slope-intercept form, so solving that for "y" will give you the slope-intercept form