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Mathematics 14 Online
OpenStudy (anonymous):

medal to best answer with explanation

OpenStudy (anonymous):

OpenStudy (anonymous):

Use those trig functions that we went over on the last problem. SOH CAH TOA

OpenStudy (anonymous):

Set up an equation and we'll go over how to get the angle :)

OpenStudy (anonymous):

uh wha?

OpenStudy (anonymous):

Each trig function relates an angle to two sides of a right triangle. \[Sin(\theta) = \frac{Opposite Side}{Hypotenuse}\] \[Cos(\theta) = \frac{Adjacent Side}{Hypotenuse}\] \[Tan(\theta) = \frac{Opposite Side}{Adjacent Side}\] You can remember this by: SOH CAH TOA. S = Sin C = Cos T = Tan O = Opposite A = Adjacent

OpenStudy (anonymous):

i don't even know... cool

OpenStudy (anonymous):

nvm

OpenStudy (anonymous):

As for what is meant by "opposite" and "adjacent," I'll draw a picture: |dw:1399248739848:dw| The hypotenuse is the side that doesn't touch the right angle (90 degree angle). The adjacent side is the side that helps make the angle. The opposite side is the side directly across the triangle from the angle.

OpenStudy (anonymous):

it's okay i give up thank's anyway's

OpenStudy (anonymous):

Don't give up :( We can get this done. I promise. It's not hard, once you get used to it.

OpenStudy (anonymous):

i don't have the slightest clue at all thank's though

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