Question

A certain part if the electromagnetic spectrum ranges from 350nm to 820nm . What is the highest frequency associated with this portion of spectrum?

Answer 1

use E = h f = h c /lambda
with wavelength lambda in m, E in J, c as d x 10^8 m/s

Answer 2

f is frequency

Answer 3

what are E and h?

Answer 4

Electric field?

Answer 5

^ that doesn't make sense, I know.

Answer 6

E =energy of photon
h= Planck's constant

Answer 7

In the plank's constant the power of 10 is " -34" not 32

Answer 8

Sorry..I had a random brain glitch.

Answer 9

^better? xD

Answer 10

Also it is 6.626 not 6.26

Answer 11

Yikes. I'm really glitching. One sec. I'll fix it.

Answer 12

E=hf=hc/λ
E-energy of a photon
h-plank's constant: 6.626*10^-34 m^2kg/sec
λ-wavelength
c-speed of light: 2.998*10^8 ms^-1
So basically use the E=hc/λ and then plug in E for E=hf
Rearrange for E/h=f
I think that's what doug is trying to get at.

Answer 13

Perfect!! :)

Answer 14

I'm like.....mixing Avogadro's number and Plank's constant....Dx gah...someone save me.

Answer 15

Actually we can find the Wavelength associated with highest frequency in a simple way!!!
E=hc/λ & E=hf
There fore f = c/λ
From this we can say that frequency is inversely proportional to wave length
Hence for the lowest Wavelength we get the highest frequency

Answer 16

*applauds*

Answer 17

Thanks :) Did you get it @Grazes