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Mathematics 20 Online
OpenStudy (anonymous):

The grades on the last math exam had a mean of 88%. Assume the population of grades on math exams is known to be normally distributed with a standard deviation of 6. What percent of students earn a score between 72% and 90%?

OpenStudy (anonymous):

you need to find the value of z for both the values given as 72 and 90 against mean 88 and then add them and finally express it as % using z= (x-88)/6 ...

OpenStudy (anonymous):

Yes and n, find z=(value-mean)/sd for 90 and for 72 as values, then use tables to get the percentages between these z values, rather than the sum of these .

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