Question

LOG 5 (0.008)

Answer 1

\(5^?=0.008\)

Answer 2

who knows?

Answer 3

Change of base formula:

\( \log_a x = \dfrac{log_b x}{log_b a} \)

Answer 4

You just wrote it in exponential form @zzr0ck3r thats what i have to find out lol

Answer 5

Is it possible to do it without the change of base formula

Answer 6

Not that I know of.

Answer 7

\( \log_5 0.008\)

\(= \log_5 0.2^3\)

\(= 3\log_5 0.2\)

\(=3 \log_5 \dfrac{1}{5} \)

\(=3 \log_5 5^{-1} \)

\(=-3 \log_5 5\)

\(= -3\)

I guess I was wrong. It can be done without changing base.

Answer 8

thank you dude!

Answer 9

A more elegant solution:

\(\log^5 0.008\)

\(= \log_5 0.2^3\)

\(= \log_5 (5^{-1})^3 \)

\(= \log_5 5^{-3} \)

\(= -3\)

Answer 10

You're welcome.