Question

A tedious calculation
(I would be posting)

Answer 1

\[\log10(2) + 16\log10(\frac{ 16 }{ 25 }) + 12\log10(\frac{ 25 }{ 24 }) + 7\log10(\frac{ 81 }{ 80})\]

Answer 2

It seems simple i have to raise to the respective powers

Answer 3

2^4=16

Answer 4

5^2=25

Answer 5

24=3*2^3

Answer 6

wait i think i got it

Answer 7

log(M/N)=logM-logN

Answer 8

logM*N=logM+logN

Answer 9

This whole damn thing simplifies
to \[\Huge \log10(10)\]
\[Huge =1\]