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Mathematics 12 Online
OpenStudy (phebe):

FAN and MEDAL SIMPLIFICATION HELPP!! I'll post the question in a sec

OpenStudy (phebe):

\[\frac{ 6 }{ \sqrt{3+2}? }\]

OpenStudy (phebe):

simplify this plz do u want answer choices

OpenStudy (phebe):

@pSelena

OpenStudy (anonymous):

add the numbers inside the root multiply top and bottom times \[\sqrt{5}\]

OpenStudy (anonymous):

yes answer choices

OpenStudy (phebe):

why multiply by squareroot of 5

OpenStudy (phebe):

@student_basil

OpenStudy (anonymous):

I thought you just multiply 3+2=6 find the squareroot then divide it into 6

OpenStudy (phebe):

3+2=5 not 6

OpenStudy (anonymous):

oh yeah sorry

OpenStudy (anonymous):

5

OpenStudy (phebe):

3+3=6 wats wrong @mathslover

OpenStudy (anonymous):

sqr(5)= 2.24/6= 2.68?

OpenStudy (phebe):

so do u know wat the answer is @B_destiny

OpenStudy (anonymous):

its 5 phebe

OpenStudy (anonymous):

2.68 or 2.70

OpenStudy (anonymous):

no its not @yahman

OpenStudy (anonymous):

yes it is

OpenStudy (anonymous):

You had to do 3+2=5 sqr(5) = 2.24 rounded.... then divide into 6

OpenStudy (anonymous):

no b destiny

OpenStudy (mathstudent55):

First, 3 + 2 = 5, not 6. Second, the reason we multiply \(\sqrt{5} \) in the denominator by \(\sqrt{5} \) is that we need to rationalize the denominator. It is not considered proper to leave a radical in the denominator. Rationalizing the denominator is the name of the process used to get rid of a radical in the denominator. Since \( \sqrt{5} \times \sqrt{5} = 5\), by multiplying the \(\sqrt{5} \) in the denominator by \(\sqrt{5} \) we get 5 in the denominator. We must also multiply the numerator by the same number, \(\sqrt5\), so we don't change the value of the fraction..

OpenStudy (anonymous):

what are the answer choices @phebe

OpenStudy (anonymous):

lmao

OpenStudy (phebe):

ok holdon @B_destiny

OpenStudy (anonymous):

UGHHHH SEE WHY I HATE MATH

OpenStudy (mathstudent55):

\(\dfrac{ 6 }{ \sqrt{3+2}}\) \(=\dfrac{ 6 }{ \sqrt{5}}\) \(=\dfrac{ 6 }{ \sqrt{5}} \times \dfrac{\sqrt5}{\sqrt5}\) \(=\dfrac{ 6 \sqrt{5}}{\sqrt{25}}\) \(=\dfrac{ 6 \sqrt{5}} {5}\)

OpenStudy (mathstudent55):

Now the fraction is rationalized since there is no radical in the denominator.

OpenStudy (anonymous):

Since your so called smart come help me with my math question

OpenStudy (phebe):

who @B_destiny

OpenStudy (mathstudent55):

Where is your question? Did you post one?

OpenStudy (mathstudent55):

@Phebe The the answer match one of the choices?

OpenStudy (anonymous):

I will repost it hold on@mathstudent55

OpenStudy (phebe):

no thas y im posting the answer choices

OpenStudy (mathstudent55):

ok

OpenStudy (phebe):

A-\[\frac{4}{\sqrt{3} ? }\] B-\[12-6\sqrt{3}\] C-\[\sqrt{3-2}\] D- 3

OpenStudy (phebe):

those are the answer choices for my question @mathstudent55

OpenStudy (anonymous):

D

OpenStudy (anonymous):

I think... thats what i got was 3

OpenStudy (phebe):

ok

OpenStudy (phebe):

thanks everybody

OpenStudy (anonymous):

welcome

OpenStudy (anonymous):

no prob phebe

OpenStudy (phebe):

XD

OpenStudy (mathstudent55):

That means the problem we solved is wrong, or the choices are wrong, or the problem and the choices are mismatched.

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