FAN and MEDAL SIMPLIFICATION HELPP!! I'll post the question in a sec
\[\frac{ 6 }{ \sqrt{3+2}? }\]
simplify this plz do u want answer choices
@pSelena
add the numbers inside the root multiply top and bottom times \[\sqrt{5}\]
yes answer choices
why multiply by squareroot of 5
@student_basil
I thought you just multiply 3+2=6 find the squareroot then divide it into 6
3+2=5 not 6
oh yeah sorry
5
3+3=6 wats wrong @mathslover
sqr(5)= 2.24/6= 2.68?
so do u know wat the answer is @B_destiny
its 5 phebe
2.68 or 2.70
no its not @yahman
yes it is
You had to do 3+2=5 sqr(5) = 2.24 rounded.... then divide into 6
no b destiny
First, 3 + 2 = 5, not 6. Second, the reason we multiply \(\sqrt{5} \) in the denominator by \(\sqrt{5} \) is that we need to rationalize the denominator. It is not considered proper to leave a radical in the denominator. Rationalizing the denominator is the name of the process used to get rid of a radical in the denominator. Since \( \sqrt{5} \times \sqrt{5} = 5\), by multiplying the \(\sqrt{5} \) in the denominator by \(\sqrt{5} \) we get 5 in the denominator. We must also multiply the numerator by the same number, \(\sqrt5\), so we don't change the value of the fraction..
what are the answer choices @phebe
lmao
ok holdon @B_destiny
UGHHHH SEE WHY I HATE MATH
\(\dfrac{ 6 }{ \sqrt{3+2}}\) \(=\dfrac{ 6 }{ \sqrt{5}}\) \(=\dfrac{ 6 }{ \sqrt{5}} \times \dfrac{\sqrt5}{\sqrt5}\) \(=\dfrac{ 6 \sqrt{5}}{\sqrt{25}}\) \(=\dfrac{ 6 \sqrt{5}} {5}\)
Now the fraction is rationalized since there is no radical in the denominator.
Since your so called smart come help me with my math question
who @B_destiny
Where is your question? Did you post one?
@Phebe The the answer match one of the choices?
I will repost it hold on@mathstudent55
no thas y im posting the answer choices
ok
A-\[\frac{4}{\sqrt{3} ? }\] B-\[12-6\sqrt{3}\] C-\[\sqrt{3-2}\] D- 3
those are the answer choices for my question @mathstudent55
D
I think... thats what i got was 3
ok
thanks everybody
welcome
no prob phebe
XD
That means the problem we solved is wrong, or the choices are wrong, or the problem and the choices are mismatched.
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