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Find the value of the series (2^n+1)/3^n.
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From n=1 to infinity.
@dumbcow @iambatman
@myininaya @RadEn
is it A) \((2^n+1)/3^n\) or B) \(2^{n+1}/3^n\) ?
B.
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ok. When seeing these powers, you might thnk about the geometric formula \[\sum_{n=0}^\infty x^n = \frac{1}{1-x}\quad\text{if } 0<x<1. \] and try to make your series look like that (factor out a few things).
So you mean that this is geometric series?
\[\frac{2^{n+1}}{3^n} = 2 (\frac{2}{3})^n\]
Got it. Thank you so much, dumbcow.
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