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@Hero
Use law of sines to help you \[\frac{\sin A}{a} = \frac{\sin B}{b}\]
Insert the given values. Let \(\sin B = x\) \[\frac{\sin 30}{2} = \frac{x}{4}\]
Solve for x, Then find Angle B
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Make sure Angle B + Angle A is less than 180
|dw:1399339109169:dw| If you drop a perpendicular from C to the horizontal base what would be the length of CB? CB = AC * sin(30) = ? That will help answer the question.
If Angle A + Angle B is greater than 180, then you only have 1 triangle. If Angle A + Angle is less than 180, then you have two triangles.
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