Question

HELP ME PLEASE (I WOULD TYPE THE QUESTION SHORTLY)

Answer 1

\[\huge If \log \frac{ x-y }{ 4 }=\log \sqrt{x} + \log \sqrt{y}\]
Then Show That
\[\huge (x+y)^{2}= 20xy\]

Answer 2

@zepdrix

Answer 3

This time i would do the question but give me some hints as i am not getting it for a long time

Answer 4

So use rules of logs to get each side written in terms of a single log.
Then exponentiate each side.

Answer 5

wait i will be doing

Answer 6

\[\huge \log \frac{ x-y }{ 4 } = \log \sqrt{xy}\]
\[\huge \frac{ (x-y)^{2} }{16 }=xy\]
\[\huge (x-y)^{2} =16xy\]
\[\huge x ^{2} + y ^{2} =18xy\]
\[\huge (x+y)^{2} -2xy =18xy\]
\[\huge (x+y)^{2} =20xy\]
\[\Huge Proved!!\]

Answer 7

Yay \c:/

Answer 8

Thank you for your help dude!