Question

Integrate:

Answer 1

\[\LARGE \int \frac{ln(x)}{x^2}~dx\]

Answer 2

Try integration by parts.

\[\int\limits_{}^{} u.dv = uv - \int\limits_{}^{}v.du\]

Take
u = ln (x)
du = dx/x

dv = x^(-2) . dx
v = -x^(-1)

That'll give you:

\[- \ln (x)/x + \int\limits_{}^{} x^{-2}.dx\]

Answer 3

And then integrate the second term, you'll have the answer.

Answer 4

Alright, thank you :)