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sec theta= -square 2
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\[sec~ \theta = -\sqrt{2}\] Now we really don't know what it represents. But what we DO know is what cos theta helps us find, ie. we know the trig. values of the cosine function: \[\frac{1}{cos ~\theta} = -\sqrt{2}\] \[cos ~\theta = -\frac{1}{\sqrt{2}}\] Now cosine is negative in the 2nd and the 3rd quadrants only. Can you find '\(\theta\)' now? :D
I think I can. thank you:)
:)
I think theta is 3pie/4 and 5pie/4?? Thank you for your help sir!
cos^2x/sin^2x +cosx secx
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