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let R be the region bounded by the graphs of the equations. Set up an Integral that can be used to find the volume of the solid generated if R is revolved about the given line. x^2 +y^2=1 x=5
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|dw:1399356883727:dw|So uhh we're spinning like this.
Have you learned about polar integration? We can convert to polar to deal with this nicely. Otherwise we can take advantage of symmetry... Find the area under the first quadrant, and multiply it by 4.
thank you for help :)
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