Question

cos theta =(squareroot70)/4 and 0 degrees 12 years ago

Answer 1

find \[\sin \theta ,then \sin 2\theta=2\sin \theta \cos \theta \]

Answer 2

@ganeshie8

Answer 3

use below to find value of \(\sin \theta\) :

\(\sin ^2 \theta + \cos^2 \theta = 1\)

Answer 4

plugin the give \(\cos \theta \) above and solve \(\sin \theta \)

Answer 5

\[1-\sqrt{70}/4\]

Answer 6

\[\frac{ \sqrt{70} }{ 4 }>1, which~ is ~\not` correct ~as \left| \cos \theta \right|\le 1\]

Answer 7

\[1-(\sqrt{70}/4)^2\]

Answer 8

check your statement.

Answer 9

im lost^^^

Answer 10

thanks

Answer 11

your question has a typo :

cos theta =(squareroot7\(\color{Red}{0}\))/4 and 0 degrees<theta<90 degrees

Answer 12

check the original question again, that \(\color{Red}{0}\) doesnt belong there ^

Answer 13

im done yea i see that now thanks for pointing out

Answer 14

np :)