Question

derivatives and functions

Answer 1

Find the limit of the function algebraically.

limit as x approaches zero of quantity negative six plus x divided by x to the fourth power.

Answer 2

by plugging in x=0, you get 0 in denominator

this means the limit is either positive or negative infinity

if numerator is positive --> lim = infinity
numerator is negative --> lim = - infinity

Answer 3

so basically i put 0^2-8 which will be -8... so its -infinity?

Answer 4

@dumbcow , it's over x^4

Answer 5

Let me interject, this is the problem as stated: limit as x approaches zero of quantity negative six plus x divided by x to the fourth power.
\[\lim_{x \rightarrow 0} \frac{-6+x}{x^4}\]

Answer 6

no i put up a drawing... and the drawings the equation i have....

Answer 7

yeah the numerator was ambiguous, but i assumed the denominator was x^4
thus in either case the lim x->0 is -infinity

Answer 8

.-. where are you guys getting a denominator from? the equation islim(x^2-8)....

Answer 9

lol
you wrote
"limit as x approaches zero of quantity negative six plus x divided by x to the fourth power."

Answer 10

yeah .-. but thats why i did a picture to fix it c:

Answer 11

oh ok, well if its just "x^2 -8" the limit is simply -8
not sure why that is a limit problem

Answer 12

.-. hummm okay so i was right! ^.^ can you help with a few more?

Answer 13

@dumbcow sorry for the confusion

Answer 14

@FibonacciChick666 , no problem at all, thanks for clarifying the problem as there was confusion