Question

Will give medal and fan

Use the equation and type the ordered-pairs.
y = 2^x

{(-1,__ a0), (0,__ a1), (1,__ a2), (2,__ a3), (3,__ a4), (4,__ a5)}

Answer 1

Alright...so this is saying to make the ordered pairs using

\[\large y = 2^x\]

The first one (a0 give (-1 , ?) so we take that -1 and plug it in for 'x' in this equation...and see what the ? would be

\[\large y = 2^{-1} = \frac{1}{2} = .5\]

So the first ordered pair a0 will be (-1 , .5)

Answer 2

and so on and so forth...

so a1 would then be what would the equation be when x = 0

\[\large y = 2^0 = 1\] so that ordered pair a1 would be (0 , 1)

Answer 3

ohhhhh alright yeah i see now thank you!

Answer 4

Anytime :)