v*t/T=? with capacitor when voltage increase linearly
If you're trying to achieve a linear voltage increase across a capacitor - the following equation is useful: \[v=(\Delta q/t)/C\] The change in charge per unit time is just the current. So, charging the capacitor with a constant current will net a linear voltage increase (or decrease) across the capacitor. If you are observing a constant voltage change - it's obviously because the charging current is constant.
Allow me to correct that equation: \[\Delta v = (\Delta q/ \Delta t)/C\] The change in charge over a change in time is the current. And the change in voltage is a function of the change in charge.per unit time. The conclusion remains unchanged - a constant charge current will result in a linear change in voltage.
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