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OpenStudy (anonymous):
ln 1/e^3
I got -1 but Im not sure if that is correct?
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OpenStudy (jtvatsim):
almost, I think you are on the right track though... let me work it out first... :)
OpenStudy (anonymous):
okay
OpenStudy (jtvatsim):
alright, so first convert 1/e^3 to negative exponents, what did you get (or does that even make sense :) )?
OpenStudy (anonymous):
thats where I got the -1, bc if its a fraction it has to come from a neg number right?
OpenStudy (jtvatsim):
or wait, that exponent might be different that thinking...
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OpenStudy (anonymous):
-3
OpenStudy (anonymous):
Charlie how did you get the answer?
OpenStudy (anonymous):
ln(e^-3), ln and e cancels each other
OpenStudy (jtvatsim):
is the question this or this?
\[\ln(\frac{1}{e^3})\]
\[[\ln(1/e)]^3\]
OpenStudy (jtvatsim):
right, I think charlie's got it :)
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OpenStudy (anonymous):
the first
OpenStudy (jtvatsim):
ok, then yes, the conversion should be e^-3 because not only is it a fraction (-1) but it is also to the third power (3) so combining gives you -3
OpenStudy (anonymous):
so when I write it out I can write it like this?
OpenStudy (anonymous):
Yes, both ways
OpenStudy (anonymous):
|dw:1399444496427:dw|
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