A system of equations is shown below. 5x - 5y = 10 3x - 2y = 2 Part A: Create an equivalent system of equations by replacing one equation with the sum of that equation and a multiple of the other. Show the steps to do this.
Please help.
The Solution to the original problem is: x = -2 y = -4 part A: 5x-5y=10 (3x-2y=2) * 2 5x-5y=10 6x-4y=4 add: 11x-9y=14 New System: 11x-9y=14 3x-2y=2 Hope this helps!:)
Yes but why did you multiply the second equation by two and not the other? Do you not have to do the same to both equations?
I just want to figure out how to do this myself to I'm not looking for anyone to give me answers.
Do you know how to solve the original equation?
Which one? There are two in the original system.
Either one.
I can find the solution of them both, by getting them into y=mx+b form and then graphing them right?
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