What number must be added to the expression below to complete the square? x^2 + x I wouldn't know how to start so go through it with me if you'd like!
add 1/4
(x+1/2)^2 is what you are looking for 1/2 (x) + 1/2(x) = x and 1/2 * 1/2 = 1/4
There's an easier method. Just divide the coefficient of the second number, x, which is one, by two. So 1/2. Then square it to get 1/4. Trust me. This method ALWAYS works.
Ax^2+Bx+C right ? Well (B/2)^2 will always equal C.
Hope this helps! :)
you want (x + b)^2 = x^2 + 1x + c where b and c are real numbers to be found expanding the left hand side: x^2 + 2bx + b^2 = x^2 + 1x + c equating individual terms 2b = 1...........(1) b^2 = c.........(2) from (1):- b = 1/2 now we substitute for b in equation (2):- (1/2)^2 = c c = 1/4 c = a/4 therefor
so we have x^2 + (1/2)x + 1/4 = ( x +1/2)^2
I dont know what happened to my posts - they got all mixed up
yes you are right Joylin - I went through it from basic principles because it seemed to me thats what johnny621 wanted.
I just elaborated and offered him a formula that'll always help him. You're method is fine as well.
So it's 1/4? Thank you all for the help! Also extra thanks for going through the method!
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