Question

What are the zeros of the polynomial function f(x) = x3 - 2x2 - 24x?

Answer 1

f(x) = x^3 - 2x^2 - 24x

Set f(x) = 0

0 = x^3 - 2x^2 - 24x

Factor out x

0 = x(x^2 - 2x - 24)

Factor x^2 - 2x - 24. Then use zero product property to finish solving for x.

Answer 2

How would I factor it? I'm terrible at this.. :/

Answer 3

Find 2 numbers that multiply to get 24 but combine to get -2

Answer 4

-6 and 4?

Answer 5

Yes correct. So x^2 -2x - 24 = (x - )(x + )

Fill in the blank

Answer 6

(x-6)(x+4)
So the answer would be -6, 0, 4?

Answer 7

So that you don't make a mistake, write out the steps like this:

0 = x(x - 6)(x + 4)

x = 0
x - 6 = 0
x + 4 = 0

x = 0
x = 6
x = -4

Answer 8

Thank you so much!