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Mathematics
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Solve the equation by applying the squaring property of equality. Be sure to check all solutions in the original equation. ( If there is no solution, enter NO SOLUTION.)
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\[\sqrt{2x+3}-3=4\] @charliealbert
\[(\sqrt{2x+3})^{2}=7\] \[2x+3=7\] \[x=2\]
2(2)+3-3=4 4+3-3=4 7-3=4 4=4!! Yes! THANK YOU! lol
@Jack1 @whpalmer4 , this one ssaid incorrect :(
sqrt (2x+3)−3=4 sqrt (2x+3)−3+3 = 4+3 [sqrt (2x+3)]^2 = [7]^2 2x+3 = 49 2x+3-3 = 49-3 2x = 46 so x = 23... in my working anywhay...?
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O sorry, I forgot to elevate the seven XD
It's ok lol
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