Question

A line that contains the points (1,-6) and (-2,6). What is the slope of a line that is perpendicular to this line?

Answer 1

slope of the line containing (x1,y1) and (x2,y2)
is m=(y2-y1)/(x2-x1)
now slope of the line perpendicular of it is m1=-(1/m)
so first calculate m

Answer 2

@sidsiddhartha I doubt she is old enough to understand that.

Answer 3

yes another method u could use
can you develop the equation of the line passing through (1,-6) (-2,6)?

Answer 4

ohhh my apologies the profile picture through me off. I should have read the description.