Question

The area of a square is 4x^4/9y^2 sq units. What is the length of one side, in units.

A. 18x^2/18y

B. 4x/9y

C. 2x^2\3y

D. 4x^2/ 6y^2

Answer 1

Area of a square is given by : \(\textbf{(side)}^2\)

It is given to you that :

Area of Square = \((\text{side})^2 = \dfrac{4x^4}{9y^2} sq. units \)

To find the side of the square :

Square root both sides :

\(\sqrt{(\text{side})^2} = \sqrt{\dfrac{4x^4}{9y^2} sq. units }\)

Thus,

side = \(\sqrt{\dfrac{(2x^2)^2}{(3y)^2} } units\)

Can you simplify it further?

Answer 2

Yes , Thank you. :)

Answer 3

You're welcome :)